day 3

In this image, I had two leds. Led-1 (red) is connected to the second positive prong of the relay, while led-2 (green) is connected to the forth positive prong of the relay. The relay's third prong is connected to power and looped to the second prong in the relay, giving power to the red led. When 9 volts goes through the coil of the relay prong 3 will be looped to prong 4 inside the relay lighting up the green led. So first, the red led comes on, then i press the button, giving power to the coil and power gets cut off to the red led and lights up the green one.

This next image is a modified version of the previous circuit. In this version, the third prong gets power at the same time as the capacitor. In the beginning, when the button is pressed the led connected to prong two will light up and the capacitor will charge. When the capacitor is charged it will dissipate its power making a circuit of its own going through the coil of the relay. When the coil gets charged prong 3 will be connected to prong 4, and the led connected to prong 4 will light up. Also when the coil is charged power will not run through the capacitor because it will no longer be connected to the loop.  When the capacitor runs low on power, the coil will no longer be charged and the relay will go back to its original state: prong 3 connected to prong 2. This will cause the led connoted to prong 2 to light up and the capacitor will be charged and the cycle will repeat.